dded mag as rel
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![[De_Broglie_Kracklauer.pdf]]
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# De-Broglie 1924 QM Thesis
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[De_Broglie_Kracklauer.pdf](De_Broglie_Kracklauer.pdf)
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@ -8,3 +8,7 @@
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[Ideas](Ideas.md)
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[Complex_probabilities](Complex_probabilities.md)
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[Straight Line Motion](Straight%20Line%20Motion.md)
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[Magnetism due to special relativity](mag_special_rel.md)
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@ -129,7 +129,7 @@ This is why the **Laplacian appears in the Schrödinger equation**.
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## Final intuition
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The wavefunction contains two things:
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The wave~function contains two things:
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**Amplitude**
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- how much probability is present
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@ -61,7 +61,7 @@ So the **divide by $2m$** simply comes from the classical kinetic energy formula
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## 2. Introduce a wave
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Quantum mechanics uses a **wavefunction** $\psi(x,t)$.
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Quantum mechanics uses a **wave~function** $\psi(x,t)$.
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Take a simple plane wave in 1D:
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@ -112,9 +112,9 @@ $$
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Substitute this into the second derivative result:
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$$
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\frac{\partial^2 \psi}{\partial x^2}
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=
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$$
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-\left(\frac{p}{\hbar}\right)^2 \psi
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=
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$$
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-\frac{p^2}{\hbar^2}\psi
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$$
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Rearrange:
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@ -150,6 +150,7 @@ $$
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E\psi = \frac{p^2}{2m}\psi + V\psi
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$$
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Replace $p^2\psi$:
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$$
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E\psi
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=
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@ -157,9 +158,7 @@ E\psi
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$$
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So
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$$
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E\psi
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=
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-\frac{\hbar^2}{2m}\frac{\partial^2 \psi}{\partial x^2} + V\psi
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E\psi = -\frac{\hbar^2}{2m}\frac{\partial^2 \psi}{\partial x^2} + V\psi
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$$
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This is where the factor
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$$
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@ -182,6 +181,7 @@ $$
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\frac{\partial \psi}{\partial t} = -i\omega \psi
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$$
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Multiply by $i\hbar$:
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$$
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i\hbar \frac{\partial \psi}{\partial t}
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=
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@ -209,6 +209,7 @@ $$
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## 7. Substitute into the equation
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We had
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$$
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E\psi =
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-\frac{\hbar^2}{2m}\frac{\partial^2 \psi}{\partial x^2}
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@ -216,6 +217,7 @@ E\psi =
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$$
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Replace $E\psi$:
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$$
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i\hbar \frac{\partial \psi}{\partial t}
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=
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@ -1,3 +1,7 @@
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# Standards Notes
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[EN298](EN298.md)
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[EN60730](EN60730.md)
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[EN61508](EN61508.md)
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@ -20,7 +20,7 @@
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[Clothing](Clothing.md)
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[Cycling](Cycling.md)
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[Juggling](Juggling.md)
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[Unicycling](Unicycling.md)
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[Uni-cycling](Unicycling.md)
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[Music](Music.md)
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